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6y^2-59y+144=0
a = 6; b = -59; c = +144;
Δ = b2-4ac
Δ = -592-4·6·144
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-5}{2*6}=\frac{54}{12} =4+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+5}{2*6}=\frac{64}{12} =5+1/3 $
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